我建议检查是否设置了$_SERVER数组的一些条目。

例如:

if (isset($_SERVER['REQUEST_METHOD'])) {
        print "HTTP request\n";
} else {
        print "CLI invocation\n";
}

Try

isset($_SERVER['REQUEST_METHOD'])

如果设置了，则是在浏览器中。

或者，你可以检查是否

isset($_SERVER['argv'])

但在windows CLI、IDK上可能不是这样。

这应该处理所有的情况(包括php-cgi)

return (php_sapi_name() === 'cli' OR defined('STDIN'));

我已经使用这个函数好几年了

function is_cli()
{
    if ( defined('STDIN') )
    {
        return true;
    }

    if ( php_sapi_name() === 'cli' )
    {
        return true;
    }

    if ( array_key_exists('SHELL', $_ENV) ) {
        return true;
    }

    if ( empty($_SERVER['REMOTE_ADDR']) and !isset($_SERVER['HTTP_USER_AGENT']) and count($_SERVER['argv']) > 0) 
    {
        return true;
    } 

    if ( !array_key_exists('REQUEST_METHOD', $_SERVER) )
    {
        return true;
    }

    return false;
}

根据http://jp2.php.net/manual/en/features.commandline.php，只有在从CLI运行时才会设置一些常量。这些常量是STDIN, STDOUT和STDERR。测试其中一个将告诉您它是否处于cli模式

php_sapi_name() is really not the best way to perform this check because it depends on checking against many possible values. The php-cgi binary can be called from the command line, from a shell script or as a cron job and (in most cases) these should also be treated as 'cli' but php_sapi_name() will return different values for these (note that this isn't the case with the plain version of PHP but you want your code to work anywhere, right?). Not to mention that next year there may be new ways to use PHP that we can't possibly know now. I'd rather not think about it when all I care about is weather I should wrap my output in HTML or not.

幸运的是，PHP有一种方法可以检查这一点。只需使用http_response_code()，不带任何参数，如果从web服务器类型环境运行，它将返回TRUE，如果从CLI类型环境运行，则返回FALSE。代码如下:

$is_web=http_response_code()!==FALSE;

即使您在调用之前不小心(?)从从CLI(或类似CLI的东西)运行的脚本设置了响应代码，这也可以工作。