我希望我的应用程序的用户能够删除DCIM文件夹(它位于SD卡上并包含子文件夹)。
这可能吗?如果可能,怎么可能?
我希望我的应用程序的用户能够删除DCIM文件夹(它位于SD卡上并包含子文件夹)。
这可能吗?如果可能,怎么可能?
当前回答
这里是一个非递归的实现,只是为了好玩:
/**
* Deletes the given folder and all its files / subfolders.
* Is not implemented in a recursive way. The "Recursively" in the name stems from the filesystem command
* @param root The folder to delete recursively
*/
public static void deleteRecursively(final File root) {
LinkedList<File> deletionQueue = new LinkedList<>();
deletionQueue.add(root);
while(!deletionQueue.isEmpty()) {
final File toDelete = deletionQueue.removeFirst();
final File[] children = toDelete.listFiles();
if(children == null || children.length == 0) {
// This is either a file or an empty directory -> deletion possible
toDelete.delete();
} else {
// Add the children before the folder because they have to be deleted first
deletionQueue.addAll(Arrays.asList(children));
// Add the folder again because we can't delete it yet.
deletionQueue.addLast(toDelete);
}
}
}
其他回答
public static void deleteDirectory( File dir )
{
if ( dir.isDirectory() )
{
String [] children = dir.list();
for ( int i = 0 ; i < children.length ; i ++ )
{
File child = new File( dir , children[i] );
if(child.isDirectory()){
deleteDirectory( child );
child.delete();
}else{
child.delete();
}
}
dir.delete();
}
}
这是kotlin选项。它运行得很好。
fun executeDelete(context: Context, paths: List<String>): Int {
return try {
val files = paths.map { File(it) }
val fileCommands = files.joinToString(separator = " ") {
if (it.isDirectory) "'${it.absolutePath}/'" else "'${it.absolutePath}'"
}
val command = "rm -rf $fileCommands"
val process = Runtime.getRuntime().exec(arrayOf("sh", "-c", command))
val result = process.waitFor()
if (result == 0) {
context.rescanPaths(paths)
}
result
} catch (e: Exception) {
-1
}
}
//避免在一行中多次调用,它可以删除整个文件夹内容
fun Context.rescanPaths(paths: List<String>, callback: (() -> Unit)? = null) {
if (paths.isEmpty()) {
callback?.invoke()
return
}
var cnt = paths.size
MediaScannerConnection.scanFile(applicationContext, paths.toTypedArray(), null) { _, _ ->
if (--cnt == 0) {
callback?.invoke()
}
}
}
这种方法适用于只包含文件的文件夹,但如果您正在寻找还包含子文件夹的场景,则需要递归
此外,您应该捕获返回的返回值,以确保允许您删除该文件
,包括
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
在你的清单上
void DeleteRecursive(File dir)
{
Log.d("DeleteRecursive", "DELETEPREVIOUS TOP" + dir.getPath());
if (dir.isDirectory())
{
String[] children = dir.list();
for (int i = 0; i < children.length; i++)
{
File temp = new File(dir, children[i]);
if (temp.isDirectory())
{
Log.d("DeleteRecursive", "Recursive Call" + temp.getPath());
DeleteRecursive(temp);
}
else
{
Log.d("DeleteRecursive", "Delete File" + temp.getPath());
boolean b = temp.delete();
if (b == false)
{
Log.d("DeleteRecursive", "DELETE FAIL");
}
}
}
}
dir.delete();
}
你可以像这样递归地删除文件和文件夹:
void deleteRecursive(File fileOrDirectory) {
if (fileOrDirectory.isDirectory())
for (File child : fileOrDirectory.listFiles())
deleteRecursive(child);
fileOrDirectory.delete();
}
这里是一个非递归的实现,只是为了好玩:
/**
* Deletes the given folder and all its files / subfolders.
* Is not implemented in a recursive way. The "Recursively" in the name stems from the filesystem command
* @param root The folder to delete recursively
*/
public static void deleteRecursively(final File root) {
LinkedList<File> deletionQueue = new LinkedList<>();
deletionQueue.add(root);
while(!deletionQueue.isEmpty()) {
final File toDelete = deletionQueue.removeFirst();
final File[] children = toDelete.listFiles();
if(children == null || children.length == 0) {
// This is either a file or an empty directory -> deletion possible
toDelete.delete();
} else {
// Add the children before the folder because they have to be deleted first
deletionQueue.addAll(Arrays.asList(children));
// Add the folder again because we can't delete it yet.
deletionQueue.addLast(toDelete);
}
}
}