我想通过他们的IP吸引游客…现在我正在使用这个(http://api.hostip.info/country.php?ip=......)

这是我的代码:

<?php

if (isset($_SERVER['HTTP_CLIENT_IP']))
{
    $real_ip_adress = $_SERVER['HTTP_CLIENT_IP'];
}

if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
{
    $real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
    $real_ip_adress = $_SERVER['REMOTE_ADDR'];
}

$cip = $real_ip_adress;
$iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip;
$creatorlocation = file_get_contents($iptolocation);

?>

好吧,它正常工作,但问题是,这返回国家代码,如US或CA.,而不是整个国家名称,如美国或加拿大。

那么,除了hostip.info提供的这些,还有什么好的选择吗?

我知道我可以编写一些代码,最终将这两个字母转换为整个国家的名称,但我实在懒得编写包含所有国家的代码……

注:出于某种原因,我不想使用任何现成的CSV文件或任何代码,将抓取这个信息为我,像ip2country现成的代码和CSV。


当前回答

这只是关于get_client_ip()功能的一个安全说明,这里的大多数答案都包含在get_geo_info_for_this_ip()的主函数中。

不要过分依赖请求头中的IP数据,如client -IP或X-Forwarded-For,因为它们很容易被欺骗,但是你应该依赖于我们的服务器和客户端$_SERVER['REMOTE_ADDR']之间实际建立的TCP连接的源IP,因为它不能被欺骗

$_SERVER['HTTP_CLIENT_IP'] // can be spoofed 
$_SERVER['HTTP_X_FORWARDED_FOR'] // can be spoofed 
$_SERVER['REMOTE_ADDR']// can't be spoofed 

获取被欺骗IP的国家是可以的,但请记住,在任何安全模型中使用这个IP(例如:禁止发送频繁请求的IP)都会破坏整个安全模型。恕我直言,我更喜欢使用实际的客户端IP,即使它是代理服务器的IP。

其他回答

我们可以使用geobytes.com来获得使用用户IP地址的位置

$user_ip = getIP();
$meta_tags = get_meta_tags('http://www.geobytes.com/IPLocator.htm?GetLocation&template=php3.txt&IPAddress=' . $user_ip);
echo '<pre>';
print_r($meta_tags);

它将返回这样的数据

Array(
    [known] => true
    [locationcode] => USCALANG
    [fips104] => US
    [iso2] => US
    [iso3] => USA
    [ison] => 840
    [internet] => US
    [countryid] => 254
    [country] => United States
    [regionid] => 126
    [region] => California
    [regioncode] => CA
    [adm1code] =>     
    [cityid] => 7275
    [city] => Los Angeles
    [latitude] => 34.0452
    [longitude] => -118.2840
    [timezone] => -08:00
    [certainty] => 53
    [mapbytesremaining] => Free
)

函数获取用户IP

function getIP(){
if (isset($_SERVER["HTTP_X_FORWARDED_FOR"])){
    $pattern = "/^(([1-9]?[0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5]).){3}([1-9]?[0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$/";
    if(preg_match($pattern, $_SERVER["HTTP_X_FORWARDED_FOR"])){
            $userIP = $_SERVER["HTTP_X_FORWARDED_FOR"];
    }else{
            $userIP = $_SERVER["REMOTE_ADDR"];
    }
}
else{
  $userIP = $_SERVER["REMOTE_ADDR"];
}
return $userIP;
}

您可以使用此代码片段。

 if($a = unserialize(file_get_contents('http://www.geoplugin.net/php.gp?ip='.$_SERVER['REMOTE_ADDR']))){
        $countrycode= $a['geoplugin_countryCode'];
        if ($countrycode=='UK' ){
            header( 'Location: https://www.example.co.uk/' ) ;exit;
        }
    }

试试这个简单的PHP函数。

<?php

function ip_info($ip = NULL, $purpose = "location", $deep_detect = TRUE) {
    $output = NULL;
    if (filter_var($ip, FILTER_VALIDATE_IP) === FALSE) {
        $ip = $_SERVER["REMOTE_ADDR"];
        if ($deep_detect) {
            if (filter_var(@$_SERVER['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP))
                $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
            if (filter_var(@$_SERVER['HTTP_CLIENT_IP'], FILTER_VALIDATE_IP))
                $ip = $_SERVER['HTTP_CLIENT_IP'];
        }
    }
    $purpose    = str_replace(array("name", "\n", "\t", " ", "-", "_"), NULL, strtolower(trim($purpose)));
    $support    = array("country", "countrycode", "state", "region", "city", "location", "address");
    $continents = array(
        "AF" => "Africa",
        "AN" => "Antarctica",
        "AS" => "Asia",
        "EU" => "Europe",
        "OC" => "Australia (Oceania)",
        "NA" => "North America",
        "SA" => "South America"
    );
    if (filter_var($ip, FILTER_VALIDATE_IP) && in_array($purpose, $support)) {
        $ipdat = @json_decode(file_get_contents("http://www.geoplugin.net/json.gp?ip=" . $ip));
        if (@strlen(trim($ipdat->geoplugin_countryCode)) == 2) {
            switch ($purpose) {
                case "location":
                    $output = array(
                        "city"           => @$ipdat->geoplugin_city,
                        "state"          => @$ipdat->geoplugin_regionName,
                        "country"        => @$ipdat->geoplugin_countryName,
                        "country_code"   => @$ipdat->geoplugin_countryCode,
                        "continent"      => @$continents[strtoupper($ipdat->geoplugin_continentCode)],
                        "continent_code" => @$ipdat->geoplugin_continentCode
                    );
                    break;
                case "address":
                    $address = array($ipdat->geoplugin_countryName);
                    if (@strlen($ipdat->geoplugin_regionName) >= 1)
                        $address[] = $ipdat->geoplugin_regionName;
                    if (@strlen($ipdat->geoplugin_city) >= 1)
                        $address[] = $ipdat->geoplugin_city;
                    $output = implode(", ", array_reverse($address));
                    break;
                case "city":
                    $output = @$ipdat->geoplugin_city;
                    break;
                case "state":
                    $output = @$ipdat->geoplugin_regionName;
                    break;
                case "region":
                    $output = @$ipdat->geoplugin_regionName;
                    break;
                case "country":
                    $output = @$ipdat->geoplugin_countryName;
                    break;
                case "countrycode":
                    $output = @$ipdat->geoplugin_countryCode;
                    break;
            }
        }
    }
    return $output;
}

?>

使用方法:

Example1:获取访问者IP地址的详细信息

<?php

echo ip_info("Visitor", "Country"); // India
echo ip_info("Visitor", "Country Code"); // IN
echo ip_info("Visitor", "State"); // Andhra Pradesh
echo ip_info("Visitor", "City"); // Proddatur
echo ip_info("Visitor", "Address"); // Proddatur, Andhra Pradesh, India

print_r(ip_info("Visitor", "Location")); // Array ( [city] => Proddatur [state] => Andhra Pradesh [country] => India [country_code] => IN [continent] => Asia [continent_code] => AS )

?>

例2:获取任意IP地址的详细信息。[支持IPV4和IPV6]

<?php

echo ip_info("173.252.110.27", "Country"); // United States
echo ip_info("173.252.110.27", "Country Code"); // US
echo ip_info("173.252.110.27", "State"); // California
echo ip_info("173.252.110.27", "City"); // Menlo Park
echo ip_info("173.252.110.27", "Address"); // Menlo Park, California, United States

print_r(ip_info("173.252.110.27", "Location")); // Array ( [city] => Menlo Park [state] => California [country] => United States [country_code] => US [continent] => North America [continent_code] => NA )

?>

使用以下服务

1) http://api.hostip.info/get_html.php?ip=12.215.42.19

2)

$json = file_get_contents('http://freegeoip.appspot.com/json/66.102.13.106');
$expression = json_decode($json);
print_r($expression);

3) http://ipinfodb.com/ip_location_api.php

这可以接受吗? 纯PHP

$country = geoip_country_code_by_name($_SERVER['REMOTE_ADDR']);
print $country;

裁判:https://www.php.net/manual/en/function.geoip-country-code-by-name.php