我想通过他们的IP吸引游客…现在我正在使用这个(http://api.hostip.info/country.php?ip=......)
这是我的代码:
<?php
if (isset($_SERVER['HTTP_CLIENT_IP']))
{
$real_ip_adress = $_SERVER['HTTP_CLIENT_IP'];
}
if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
{
$real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
$real_ip_adress = $_SERVER['REMOTE_ADDR'];
}
$cip = $real_ip_adress;
$iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip;
$creatorlocation = file_get_contents($iptolocation);
?>
好吧，它正常工作，但问题是，这返回国家代码，如US或CA.，而不是整个国家名称，如美国或加拿大。
那么，除了hostip.info提供的这些，还有什么好的选择吗?
我知道我可以编写一些代码，最终将这两个字母转换为整个国家的名称，但我实在懒得编写包含所有国家的代码……
注:出于某种原因，我不想使用任何现成的CSV文件或任何代码，将抓取这个信息为我，像ip2country现成的代码和CSV。
在code.google上查看php-ip-2-country。他们提供的数据库每天都会更新，所以如果你拥有自己的SQL服务器，就没有必要连接到外部服务器进行检查。所以使用代码你只需要输入:
<?php
$ip = $_SERVER['REMOTE_ADDR'];
if(!empty($ip)){
require('./phpip2country.class.php');
/**
* Newest data (SQL) avaliable on project website
* @link http://code.google.com/p/php-ip-2-country/
*/
$dbConfigArray = array(
'host' => 'localhost', //example host name
'port' => 3306, //3306 -default mysql port number
'dbName' => 'ip_to_country', //example db name
'dbUserName' => 'ip_to_country', //example user name
'dbUserPassword' => 'QrDB9Y8CKMdLDH8Q', //example user password
'tableName' => 'ip_to_country', //example table name
);
$phpIp2Country = new phpIp2Country($ip,$dbConfigArray);
$country = $phpIp2Country->getInfo(IP_COUNTRY_NAME);
echo $country;
?>
示例代码(来自资源)
<?
require('phpip2country.class.php');
$dbConfigArray = array(
'host' => 'localhost', //example host name
'port' => 3306, //3306 -default mysql port number
'dbName' => 'ip_to_country', //example db name
'dbUserName' => 'ip_to_country', //example user name
'dbUserPassword' => 'QrDB9Y8CKMdLDH8Q', //example user password
'tableName' => 'ip_to_country', //example table name
);
$phpIp2Country = new phpIp2Country('213.180.138.148',$dbConfigArray);
print_r($phpIp2Country->getInfo(IP_INFO));
?>
输出
Array
(
[IP_FROM] => 3585376256
[IP_TO] => 3585384447
[REGISTRY] => RIPE
[ASSIGNED] => 948758400
[CTRY] => PL
[CNTRY] => POL
[COUNTRY] => POLAND
[IP_STR] => 213.180.138.148
[IP_VALUE] => 3585378964
[IP_FROM_STR] => 127.255.255.255
[IP_TO_STR] => 127.255.255.255
)
我们可以使用geobytes.com来获得使用用户IP地址的位置
$user_ip = getIP();
$meta_tags = get_meta_tags('http://www.geobytes.com/IPLocator.htm?GetLocation&template=php3.txt&IPAddress=' . $user_ip);
echo '<pre>';
print_r($meta_tags);
它将返回这样的数据
Array(
[known] => true
[locationcode] => USCALANG
[fips104] => US
[iso2] => US
[iso3] => USA
[ison] => 840
[internet] => US
[countryid] => 254
[country] => United States
[regionid] => 126
[region] => California
[regioncode] => CA
[adm1code] =>
[cityid] => 7275
[city] => Los Angeles
[latitude] => 34.0452
[longitude] => -118.2840
[timezone] => -08:00
[certainty] => 53
[mapbytesremaining] => Free
)
函数获取用户IP
function getIP(){
if (isset($_SERVER["HTTP_X_FORWARDED_FOR"])){
$pattern = "/^(([1-9]?[0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5]).){3}([1-9]?[0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$/";
if(preg_match($pattern, $_SERVER["HTTP_X_FORWARDED_FOR"])){
$userIP = $_SERVER["HTTP_X_FORWARDED_FOR"];
}else{
$userIP = $_SERVER["REMOTE_ADDR"];
}
}
else{
$userIP = $_SERVER["REMOTE_ADDR"];
}
return $userIP;
}
您可以使用http://ip-api.com上的web服务
在PHP代码中，执行如下操作:
<?php
$ip = $_REQUEST['REMOTE_ADDR']; // the IP address to query
$query = @unserialize(file_get_contents('http://ip-api.com/php/'.$ip));
if($query && $query['status'] == 'success') {
echo 'Hello visitor from '.$query['country'].', '.$query['city'].'!';
} else {
echo 'Unable to get location';
}
?>
查询有许多其他信息:
array (
'status' => 'success',
'country' => 'COUNTRY',
'countryCode' => 'COUNTRY CODE',
'region' => 'REGION CODE',
'regionName' => 'REGION NAME',
'city' => 'CITY',
'zip' => ZIP CODE,
'lat' => LATITUDE,
'lon' => LONGITUDE,
'timezone' => 'TIME ZONE',
'isp' => 'ISP NAME',
'org' => 'ORGANIZATION NAME',
'as' => 'AS NUMBER / NAME',
'query' => 'IP ADDRESS USED FOR QUERY',
)
