我如何从AndroidManifest.xml文件下载后,不安装它,以编程方式获得我的apk的版本代码或版本名。
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="xxx.xx.xxx"
android:versionCode="1"
android:versionName="1.1" >
例如,我想检查我的IIS服务上是否上传了新版本,在设备上安装后,如果不是新版本,我就不想安装它。
现在我可以成功地从二进制XML数据中检索APK文件的版本。
这个主题是我得到答案的关键(我还添加了我的Ribo代码版本):
如何解析。apk包内的AndroidManifest.xml文件
此外,下面是我编写的XML解析代码,专门用于获取版本:
XML解析
/**
* Verifies at Conductor APK path if package version if newer
*
* @return True if package found is newer, false otherwise
*/
public static boolean checkIsNewVersion(String conductorApkPath) {
boolean newVersionExists = false;
// Decompress found APK's Manifest XML
// Source: https://stackoverflow.com/questions/2097813/how-to-parse-the-androidmanifest-xml-file-inside-an-apk-package/4761689#4761689
try {
if ((new File(conductorApkPath).exists())) {
JarFile jf = new JarFile(conductorApkPath);
InputStream is = jf.getInputStream(jf.getEntry("AndroidManifest.xml"));
byte[] xml = new byte[is.available()];
int br = is.read(xml);
//Tree tr = TrunkFactory.newTree();
String xmlResult = SystemPackageTools.decompressXML(xml);
//prt("XML\n"+tr.list());
if (!xmlResult.isEmpty()) {
InputStream in = new ByteArrayInputStream(xmlResult.getBytes());
// Source: http://developer.android.com/training/basics/network-ops/xml.html
XmlPullParser parser = Xml.newPullParser();
parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
parser.setInput(in, null);
parser.nextTag();
String name = parser.getName();
if (name.equalsIgnoreCase("Manifest")) {
String pakVersion = parser.getAttributeValue(null, "versionName");
//NOTE: This is specific to my project. Replace with whatever is relevant on your side to fetch your project's version
String curVersion = SharedData.getPlayerVersion();
int isNewer = SystemPackageTools.compareVersions(pakVersion, curVersion);
newVersionExists = (isNewer == 1);
}
}
}
} catch (Exception ex) {
android.util.Log.e(TAG, "getIntents, ex: "+ex);
ex.printStackTrace();
}
return newVersionExists;
}
版本比较(见上一代码段中的SystemPackageTools.compareVersions)
注意:这段代码的灵感来自以下主题:在Java中比较版本字符串的有效方法
/**
* Compare 2 version strings and tell if the first is higher, equal or lower
* Source: https://stackoverflow.com/questions/6701948/efficient-way-to-compare-version-strings-in-java
*
* @param ver1 Reference version
* @param ver2 Comparison version
*
* @return 1 if ver1 is higher, 0 if equal, -1 if ver1 is lower
*/
public static final int compareVersions(String ver1, String ver2) {
String[] vals1 = ver1.split("\\.");
String[] vals2 = ver2.split("\\.");
int i=0;
while(i<vals1.length&&i<vals2.length&&vals1[i].equals(vals2[i])) {
i++;
}
if (i<vals1.length&&i<vals2.length) {
int diff = Integer.valueOf(vals1[i]).compareTo(Integer.valueOf(vals2[i]));
return diff<0?-1:diff==0?0:1;
}
return vals1.length<vals2.length?-1:vals1.length==vals2.length?0:1;
}
我希望这能有所帮助。