我发现了其他两个解决方案，如果你知道行号，但没有其他(没有grep可能):

假设你需要第20到40行，

sed -n '20,40p;41q' file_name

or

awk 'FNR>=20 && FNR<=40' file_name

When using sed it is more efficient to quit processing after having printed the last line than continue processing until the end of the file. This is especially important in the case of large files and printing lines at the beginning. In order to do so, the sed command above introduces the instruction 41q in order to stop processing after line 41 because in the example we are interested in lines 20-40 only. You will need to change the 41 to whatever the last line you are interested in is, plus one.

Sed还需要读取数据来计算行数。 唯一可能的快捷方式是文件中有上下文/顺序可以操作。例如，如果日志行前面有固定宽度的时间/日期等。 您可以使用look Unix实用程序在文件中查找特定的日期/时间

你可以说GNU-grep

grep --context=10 ...

你可以使用ex命令，一个标准的Unix编辑器(现在是Vim的一部分)，例如。

显示单行(例如第二行): Ex +2p -scq file.txt 对应的sed语法:sed -n '2p' file.txt 行范围(例如2-5行): Ex +2,5p -scq file.txt Sed语法:Sed -n '2,5p' file.txt 从给定的行到末尾(例如，第5行到文件末尾): Ex +5,p -scq file.txt Sed语法:Sed -n '2，$p' file.txt 多行范围(例如2-4行和6-8行): Ex +2,4p +6,8p -scq file.txt Sed语法:Sed -n '2,4p;6,8p' file.txt

以上命令可以用下面的测试文件进行测试:

seq 1 20 > file.txt

解释:

+或-c后跟命令-读取文件后执行(vi/vim)命令， -s -静默模式，也使用当前终端作为默认输出， Q后面加-c是退出编辑器的命令(add !强制退出，例如-scq!)。

打印行5

sed -n '5p' file.txt
sed '5q' file.txt

打印第5行以外的所有内容

`sed '5d' file.txt

我用谷歌创建的

#!/bin/bash
#removeline.sh
#remove deleting it comes move line xD

usage() {                                 # Function: Print a help message.
  echo "Usage: $0 -l LINENUMBER -i INPUTFILE [ -o OUTPUTFILE ]"
  echo "line is removed from INPUTFILE"
  echo "line is appended to OUTPUTFILE"
}
exit_abnormal() {                         # Function: Exit with error.
  usage
  exit 1
}

while getopts l:i:o:b flag
do
    case "${flag}" in
        l) line=${OPTARG};;
        i) input=${OPTARG};;
        o) output=${OPTARG};;
    esac
done

if [ -f tmp ]; then
echo "Temp file:tmp exist. delete it yourself :)"
exit
fi

if [ -f "$input" ]; then
   re_isanum='^[0-9]+$'
   if ! [[ $line =~ $re_isanum ]] ; then
      echo "Error: LINENUMBER must be a positive, whole number."
      exit 1
   elif [ $line -eq "0" ]; then
      echo "Error: LINENUMBER must be greater than zero."
      exit_abnormal
   fi
   if [ ! -z $output ]; then
      sed -n "${line}p" $input >> $output
   fi
   if [ ! -z $input ]; then
      # remove this sed command and this comes move line to other file
      sed "${line}d" $input > tmp && cp tmp $input
   fi
fi

if [ -f tmp ]; then
rm tmp
fi

你可以试试这个命令:

egrep -n "*" <filename> | egrep "<line number>"