如果我们网站的用户使用的是v9之前版本的Internet Explorer,我希望将他们弹出到一个错误页面。不值得我们花时间和金钱去支持iev9之前的版本。所有其他非ie浏览器的用户都没问题,不应该被弹出。以下是提议的代码:
if(navigator.appName.indexOf("Internet Explorer")!=-1){ //yeah, he's using IE
var badBrowser=(
navigator.appVersion.indexOf("MSIE 9")==-1 && //v9 is ok
navigator.appVersion.indexOf("MSIE 1")==-1 //v10, 11, 12, etc. is fine too
);
if(badBrowser){
// navigate to error page
}
}
这段代码能行吗?
为了阻止一些可能会出现在我面前的评论:
Yes, I know that users can forge their useragent string. I'm not concerned.
Yes, I know that programming pros prefer sniffing out feature-support instead of browser-type but I don't feel this approach makes sense in this case. I already know that all (relevant) non-IE browsers support the features that I need and that all pre-v9 IE browsers don't. Checking feature by feature throughout the site would be a waste.
Yes, I know that someone trying to access the site using IE v1 (or >= 20) wouldn't get 'badBrowser' set to true and the warning page wouldn't be displayed properly. That's a risk we're willing to take.
Yes, I know that Microsoft has "conditional comments" that can be used for precise browser version detection. IE no longer supports conditional comments as of IE 10, rendering this approach absolutely useless.
还有其他明显需要注意的问题吗?
检测IE及其版本再容易不过了,你所需要的只是一点原生/香草Javascript:
var uA = navigator.userAgent;
var browser = null;
var ieVersion = null;
if (uA.indexOf('MSIE 6') >= 0) {
browser = 'IE';
ieVersion = 6;
}
if (uA.indexOf('MSIE 7') >= 0) {
browser = 'IE';
ieVersion = 7;
}
if (document.documentMode) { // as of IE8
browser = 'IE';
ieVersion = document.documentMode;
}
下面是一种用法:
if (browser == 'IE' && ieVersion <= 9)
document.documentElement.className += ' ie9-';
.
适用于所有IE版本,包括更高版本的低兼容性视图/模式,documentMode是IE专有的。
如微软参考页所述,IE版本10不再支持条件注释。
var ieDetector = function() {
var browser = { // browser object
verIE: null,
docModeIE: null,
verIEtrue: null,
verIE_ua: null
},
tmp;
tmp = document.documentMode;
try {
document.documentMode = "";
} catch (e) {};
browser.isIE = typeof document.documentMode == "number" || eval("/*@cc_on!@*/!1");
try {
document.documentMode = tmp;
} catch (e) {};
// We only let IE run this code.
if (browser.isIE) {
browser.verIE_ua =
(/^(?:.*?[^a-zA-Z])??(?:MSIE|rv\s*\:)\s*(\d+\.?\d*)/i).test(navigator.userAgent || "") ?
parseFloat(RegExp.$1, 10) : null;
var e, verTrueFloat, x,
obj = document.createElement("div"),
CLASSID = [
"{45EA75A0-A269-11D1-B5BF-0000F8051515}", // Internet Explorer Help
"{3AF36230-A269-11D1-B5BF-0000F8051515}", // Offline Browsing Pack
"{89820200-ECBD-11CF-8B85-00AA005B4383}"
];
try {
obj.style.behavior = "url(#default#clientcaps)"
} catch (e) {};
for (x = 0; x < CLASSID.length; x++) {
try {
browser.verIEtrue = obj.getComponentVersion(CLASSID[x], "componentid").replace(/,/g, ".");
} catch (e) {};
if (browser.verIEtrue) break;
};
verTrueFloat = parseFloat(browser.verIEtrue || "0", 10);
browser.docModeIE = document.documentMode ||
((/back/i).test(document.compatMode || "") ? 5 : verTrueFloat) ||
browser.verIE_ua;
browser.verIE = verTrueFloat || browser.docModeIE;
};
return {
isIE: browser.isIE,
Version: browser.verIE
};
}();
document.write('isIE: ' + ieDetector.isIE + "<br />");
document.write('IE Version Number: ' + ieDetector.Version);
然后使用:
if((ieDetector.isIE) && (ieDetector.Version <= 9))
{
}
如果你需要删除IE浏览器版本,那么你可以按照下面的代码。这段代码适用于IE6到IE11版本
<!DOCTYPE html>
<html>
<body>
<p>Click on Try button to check IE Browser version.</p>
<button onclick="getInternetExplorerVersion()">Try it</button>
<p id="demo"></p>
<script>
function getInternetExplorerVersion() {
var ua = window.navigator.userAgent;
var msie = ua.indexOf("MSIE ");
var rv = -1;
if (msie > 0 || !!navigator.userAgent.match(/Trident.*rv\:11\./)) // If Internet Explorer, return version number
{
if (isNaN(parseInt(ua.substring(msie + 5, ua.indexOf(".", msie))))) {
//For IE 11 >
if (navigator.appName == 'Netscape') {
var ua = navigator.userAgent;
var re = new RegExp("Trident/.*rv:([0-9]{1,}[\.0-9]{0,})");
if (re.exec(ua) != null) {
rv = parseFloat(RegExp.$1);
alert(rv);
}
}
else {
alert('otherbrowser');
}
}
else {
//For < IE11
alert(parseInt(ua.substring(msie + 5, ua.indexOf(".", msie))));
}
return false;
}}
</script>
</body>
</html>