在JavaScript中检测IE版本(v9之前)

如果我们网站的用户使用的是v9之前版本的Internet Explorer，我希望将他们弹出到一个错误页面。不值得我们花时间和金钱去支持iev9之前的版本。所有其他非ie浏览器的用户都没问题，不应该被弹出。以下是提议的代码:

if(navigator.appName.indexOf("Internet Explorer")!=-1){     //yeah, he's using IE
    var badBrowser=(
        navigator.appVersion.indexOf("MSIE 9")==-1 &&   //v9 is ok
        navigator.appVersion.indexOf("MSIE 1")==-1  //v10, 11, 12, etc. is fine too
    );

    if(badBrowser){
        // navigate to error page
    }
}

这段代码能行吗?

为了阻止一些可能会出现在我面前的评论:

Yes, I know that users can forge their useragent string. I'm not concerned. Yes, I know that programming pros prefer sniffing out feature-support instead of browser-type but I don't feel this approach makes sense in this case. I already know that all (relevant) non-IE browsers support the features that I need and that all pre-v9 IE browsers don't. Checking feature by feature throughout the site would be a waste. Yes, I know that someone trying to access the site using IE v1 (or >= 20) wouldn't get 'badBrowser' set to true and the warning page wouldn't be displayed properly. That's a risk we're willing to take. Yes, I know that Microsoft has "conditional comments" that can be used for precise browser version detection. IE no longer supports conditional comments as of IE 10, rendering this approach absolutely useless.

还有其他明显需要注意的问题吗?

当前回答

我为此做了一个方便的下划线混合。

_.isIE();        // Any version of IE?
_.isIE(9);       // IE 9?
_.isIE([7,8,9]); // IE 7, 8 or 9?

_.mixin({ isIE: function(mixed) { if (_.isUndefined(mixed)) { mixed = [7, 8, 9, 10, 11]; } else if (_.isNumber(mixed)) { mixed = [mixed]; } for (var j = 0; j < mixed.length; j++) { var re; switch (mixed[j]) { case 11: re = /Trident.*rv\:11\./g; break; case 10: re = /MSIE\s10\./g; break; case 9: re = /MSIE\s9\./g; break; case 8: re = /MSIE\s8\./g; break; case 7: re = /MSIE\s7\./g; break; } if (!!window.navigator.userAgent.match(re)) { return true; } } return false; } }); console.log(_.isIE()); console.log(_.isIE([7, 8, 9])); console.log(_.isIE(11)); <script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

2016-05-23 19:11:34

其他回答

此函数将返回IE主版本号为整数，如果浏览器不是Internet Explorer，则未定义。像所有用户代理解决方案一样，这很容易受到用户代理欺骗(这是IE版本8以来的官方功能)。

function getIEVersion() {
    var match = navigator.userAgent.match(/(?:MSIE |Trident\/.*; rv:)(\d+)/);
    return match ? parseInt(match[1]) : undefined;
}

2014-05-16 14:56:09

轻松检测MSIE (v6 - v7 - v8 - v9 - v10 - v11):

if (navigator.userAgent.indexOf('MSIE') !== -1 || navigator.appVersion.indexOf('Trident/') > 0) {
   // MSIE
}

2013-12-05 21:58:05

这对我很有用。我用它来重定向到一个页面，解释为什么我们不喜欢< IE9，并提供链接到我们更喜欢的浏览器。

<!--[if lt IE 9]>
<meta http-equiv="refresh" content="0;URL=http://google.com">
<![endif]-->

2013-01-25 19:49:21

它帮助了我

function IsIE8Browser() {
  var rv = -1;
  var ua = navigator.userAgent;
  var re = new RegExp("Trident\/([0-9]{1,}[\.0-9]{0,})");
  if (re.exec(ua) != null) {
    rv = parseFloat(RegExp.$1);
  }
  return (rv == 4);
}

2018-01-30 07:30:50

这个问题已经被回答得死去活来了，但你只需要这个。

!!navigator.userAgent.match(/msie\s[5-8]/i)

2016-02-17 16:39:59

在JavaScript中检测IE版本(v9之前)

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