出于调试的原因，我想列出一个Intent的所有附加项(以及它们的值)。现在，拿到钥匙不是问题
Set<String> keys = intent.getExtras().keySet();
但是获取键的值对我来说是一个，因为有些值是字符串，有些是布尔值……如何在循环中获取值(遍历键)并将值写入日志文件?谢谢你的提示!
当前回答
Sorry if this is too verbose or too late, but this was the only way I could find to get the job done. The most complicating factor was the fact that java does not have pass by reference functions, so the get---Extra methods need a default to return and cannot modify a boolean value to tell whether or not the default value is being returned by chance, or because the results were not favorable. For this purpose, it would have been nicer to have the method raise an exception than to have it return a default.
我在这里找到了我的信息:Android意图文档。
//substitute your own intent here
Intent intent = new Intent();
intent.putExtra("first", "hello");
intent.putExtra("second", 1);
intent.putExtra("third", true);
intent.putExtra("fourth", 1.01);
// convert the set to a string array
设置文档
String[] anArray = {};
Set<String> extras1 = (Set<String>) intent.getExtras().keySet();
String[] extras = (String[]) extras1.toArray(anArray);
// an arraylist to hold all of the strings
// rather than putting strings in here, you could display them
ArrayList<String> endResult = new ArrayList<String>();
for (int i=0; i<extras.length; i++) {
//try using as a String
String aString = intent.getStringExtra(extras[i]);
// is a string, because the default return value for a non-string is null
if (aString != null) {
endResult.add(extras[i] + " : " + aString);
}
// not a string
else {
// try the next data type, int
int anInt = intent.getIntExtra(extras[i], 0);
// is the default value signifying that either it is not an int or that it happens to be 0
if (anInt == 0) {
// is an int value that happens to be 0, the same as the default value
if (intent.getIntExtra(extras[i], 1) != 1) {
endResult.add(extras[i] + " : " + Integer.toString(anInt));
}
// not an int value
// try double (also works for float)
else {
double aDouble = intent.getDoubleExtra(extras[i], 0.0);
// is the same as the default value, but does not necessarily mean that it is not double
if (aDouble == 0.0) {
// just happens that it was 0.0 and is a double
if (intent.getDoubleExtra(extras[i], 1.0) != 1.0) {
endResult.add(extras[i] + " : " + Double.toString(aDouble));
}
// keep looking...
else {
// lastly check for boolean
boolean aBool = intent.getBooleanExtra(extras[i], false);
// same as default, but not necessarily not a bool (still could be a bool)
if (aBool == false) {
// it is a bool!
if (intent.getBooleanExtra(extras[i], true) != true) {
endResult.add(extras[i] + " : " + Boolean.toString(aBool));
}
else {
//well, the road ends here unless you want to add some more data types
}
}
// it is a bool
else {
endResult.add(extras[i] + " : " + Boolean.toString(aBool));
}
}
}
// is a double
else {
endResult.add(extras[i] + " : " + Double.toString(aDouble));
}
}
}
// is an int value
else {
endResult.add(extras[i] + " : " + Integer.toString(anInt));
}
}
}
// to display at the end
for (int i=0; i<endResult.size(); i++) {
Toast.makeText(this, endResult.get(i), Toast.LENGTH_SHORT).show();
}
其他回答
Sorry if this is too verbose or too late, but this was the only way I could find to get the job done. The most complicating factor was the fact that java does not have pass by reference functions, so the get---Extra methods need a default to return and cannot modify a boolean value to tell whether or not the default value is being returned by chance, or because the results were not favorable. For this purpose, it would have been nicer to have the method raise an exception than to have it return a default.
我在这里找到了我的信息:Android意图文档。
//substitute your own intent here
Intent intent = new Intent();
intent.putExtra("first", "hello");
intent.putExtra("second", 1);
intent.putExtra("third", true);
intent.putExtra("fourth", 1.01);
// convert the set to a string array
设置文档
String[] anArray = {};
Set<String> extras1 = (Set<String>) intent.getExtras().keySet();
String[] extras = (String[]) extras1.toArray(anArray);
// an arraylist to hold all of the strings
// rather than putting strings in here, you could display them
ArrayList<String> endResult = new ArrayList<String>();
for (int i=0; i<extras.length; i++) {
//try using as a String
String aString = intent.getStringExtra(extras[i]);
// is a string, because the default return value for a non-string is null
if (aString != null) {
endResult.add(extras[i] + " : " + aString);
}
// not a string
else {
// try the next data type, int
int anInt = intent.getIntExtra(extras[i], 0);
// is the default value signifying that either it is not an int or that it happens to be 0
if (anInt == 0) {
// is an int value that happens to be 0, the same as the default value
if (intent.getIntExtra(extras[i], 1) != 1) {
endResult.add(extras[i] + " : " + Integer.toString(anInt));
}
// not an int value
// try double (also works for float)
else {
double aDouble = intent.getDoubleExtra(extras[i], 0.0);
// is the same as the default value, but does not necessarily mean that it is not double
if (aDouble == 0.0) {
// just happens that it was 0.0 and is a double
if (intent.getDoubleExtra(extras[i], 1.0) != 1.0) {
endResult.add(extras[i] + " : " + Double.toString(aDouble));
}
// keep looking...
else {
// lastly check for boolean
boolean aBool = intent.getBooleanExtra(extras[i], false);
// same as default, but not necessarily not a bool (still could be a bool)
if (aBool == false) {
// it is a bool!
if (intent.getBooleanExtra(extras[i], true) != true) {
endResult.add(extras[i] + " : " + Boolean.toString(aBool));
}
else {
//well, the road ends here unless you want to add some more data types
}
}
// it is a bool
else {
endResult.add(extras[i] + " : " + Boolean.toString(aBool));
}
}
}
// is a double
else {
endResult.add(extras[i] + " : " + Double.toString(aDouble));
}
}
}
// is an int value
else {
endResult.add(extras[i] + " : " + Integer.toString(anInt));
}
}
}
// to display at the end
for (int i=0; i<endResult.size(); i++) {
Toast.makeText(this, endResult.get(i), Toast.LENGTH_SHORT).show();
}
Bundle的get(String key)方法返回一个对象。最好的方法是旋转键集，在每个键上调用get(String)，并在对象上使用toString()来输出它们。这对于基本类型最有效，但是对于没有实现toString()的对象，可能会遇到问题。
在Kotlin中将它作为一个用“，”分隔的字符串!
val extras = intent?.extras?.keySet()?.map { "$it: ${intent.extras?.get(it)}" }?.joinToString { it }
基于ruX的答案。
你可以使用for(字符串键:键){对象o = get(键);为了返回一个对象，在它上调用getClass().getName()来获得类型，然后做一组if name.equals("String")类型的事情来计算出你实际上应该调用哪个方法，以获得值?
以下是我用来获取非法(第三方)意图信息的方法:
Bundle bundle = intent.getExtras();
if (bundle != null) {
for (String key : bundle.keySet()) {
Log.e(TAG, key + " : " + (bundle.get(key) != null ? bundle.get(key) : "NULL"));
}
}
确保在循环之前检查bundle是否为空。
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