Laravel雄辩的《WHERE NOT IN》

我有麻烦写在laravel雄辩的ORM查询。

我的问题是

SELECT book_name,dt_of_pub,pub_lang,no_page,book_price  
FROM book_mast        
WHERE book_price NOT IN (100,200);

现在我想把这个问题转换成laravel雄辩。

当前回答

$created_po = array();
     $challan = modelname::where('fieldname','!=', 0)->get();
     // dd($challan);
     foreach ($challan as $rec){
         $created_po[] = array_push($created_po,$rec->fieldname);
     }
     $data = modelname::whereNotIn('fieldname',$created_po)->orderBy('fieldname','desc')->with('modelfunction')->get();

2020-12-22 04:38:27

其他回答

它只是意味着你有一个值的数组，你想记录除了values/records。

你可以简单地传递一个数组到whereNotIn() laravel函数。

使用查询生成器

$users = DB::table('applications')
                    ->whereNotIn('id', [1,3,5]) 
                    ->get(); //will return without applications which contain this id's

有说服力的。

$result = ModelClassName::select('your_column_name')->whereNotIn('your_column_name', ['satatus1', 'satatus2']); //return without application which contain this status.

2020-06-13 06:52:35

可以通过以下方式使用WhereNotIn:

$category=DB::table('category')
          ->whereNotIn('category_id',[14 ,15])
          ->get();`enter code here`

2019-01-01 19:52:43

实现whereNotIn的动态方式:

 $users = User::where('status',0)->get();
    foreach ($users as $user) {
                $data[] = $user->id;
            }
    $available = User::orderBy('name', 'DEC')->whereNotIn('id', $data)->get();

2018-10-28 09:56:13

你也可以用下面的方式使用WhereNotIn:

ModelName::whereNotIn('book_price', [100,200])->get(['field_name1','field_name2']);

这将返回具有特定字段的Record集合

2017-01-27 08:50:32

$created_po = array();
     $challan = modelname::where('fieldname','!=', 0)->get();
     // dd($challan);
     foreach ($challan as $rec){
         $created_po[] = array_push($created_po,$rec->fieldname);
     }
     $data = modelname::whereNotIn('fieldname',$created_po)->orderBy('fieldname','desc')->with('modelfunction')->get();

2020-12-22 04:38:27

Laravel雄辩的《WHERE NOT IN》

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