如何使用javascript正则表达式将字符串转换为驼峰大小写?

设备类名称或 设备类名或设备类名或设备类名

应该全部变成:equipmentClassName。


当前回答

为了有效地创建一个将字符串的大小写转换为驼峰式大小写的函数,该函数还需要首先将每个字符串转换为小写,然后再将非第一个字符串的第一个字符转换为大写字母。

我的示例字符串是:

"text That I WaNt to make cAMEL case"

对于这个问题提供的许多其他解决方案返回这个:

"textThatIWaNtToMakeCAMELCase"

我认为应该是预期的,期望的输出将是这样的,其中所有的中间字符串大写字符首先转换为小写:

"textThatIWanrtToMakeCamelCase"

这可以在不使用任何replace()方法调用的情况下完成,通过使用String.prototype.split(), Array.prototype.map()和Array.prototype.join()方法:

≤ES5版本

function makeCamelCase(str) {
  return str
    .split(' ')
    .map((e,i) => i
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      : e.toLowerCase()
    )
    .join('')
}

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

我将分解每一行的功能,然后以其他两种格式提供相同的解决方案——ES6格式和字符串格式。prototype方法,不过我建议不要像这样直接扩展内置的JavaScript原型。

讲解员

function makeCamelCase(str) {
  return str
    // split string into array of different words by splitting at spaces
    .split(' ')
    // map array of words into two different cases, one for the first word (`i == false`) and one for all other words in the array (where `i == true`). `i` is a parameter that denotes the current index of the array item being evaluated. Because indexes start at `0` and `0` is a "falsy" value, we can use the false/else case of this ternary expression to match the first string where `i === 0`.
    .map((e,i) => i
      // for all non-first words, use a capitalized form of the first character + the lowercase version of the rest of the word (excluding the first character using the slice() method)
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      // for the first word, we convert the entire word to lowercase
      : e.toLowerCase()
    )
    // finally, we join the different strings back together into a single string without spaces, our camel-cased string
    .join('')
}

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

压缩ES6+(一行程序)版本

const makeCamelCase = str => str.split(' ').map((e,i) => i ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase() : e.toLowerCase()).join('')

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

字符串。原型方法版本

String.prototype.toCamelCase = function() {
  return this
    .split(' ')
    .map((e,i) => i
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      : e.toLowerCase()
    )
    .join('')
}

"text That I WaNt to make cAMEL case".toCamelCase()
// -> "textThatIWanrtToMakeCamelCase" ✅

其他回答

一个超级简单的方法,使用turboCommons库:

npm install turbocommons-es5

<script src="turbocommons-es5/turbocommons-es5.js"></script>

<script>
    var StringUtils = org_turbocommons.StringUtils;
    console.log(StringUtils.formatCase('EquipmentClass', StringUtils.FORMAT_LOWER_CAMEL_CASE));
    console.log(StringUtils.formatCase('Equipment className', StringUtils.FORMAT_LOWER_CAMEL_CASE));
    console.log(StringUtils.formatCase('equipment class name', StringUtils.FORMAT_LOWER_CAMEL_CASE));
    console.log(StringUtils.formatCase('Equipment Class Name', StringUtils.FORMAT_LOWER_CAMEL_CASE));
</script>

你也可以使用StringUtils。FORMAT_CAMEL_CASE和StringUtils。FORMAT_UPPER_CAMEL_CASE生成首字母大小写的变化。

更多信息:

将字符串转换为驼峰,UpperCamelCase或lowerCamelCase

简单容易理解这段代码,希望这对你有帮助,我用下面的逻辑解决了我的问题

// This example is for React Js User

const ConverToCamelCaseString = (StringValues)=> 
{
    let WordsArray = StringValues.split(" ");
    let CamelCaseValue = '';
    for (let index = 0; index < WordsArray.length; index++) 
    {
        let singleWord = WordsArray[index];
            singleWord.charAt(0).toUpperCase();
            singleWord =singleWord.charAt(0).toUpperCase() + singleWord.slice(1);

        CamelCaseValue +=" "+singleWord;
        
    }
    CamelCaseValue = CamelCaseValue.trim();
    return CamelCaseValue;
}

下面的例子是针对核心javaScript用户的

function ConverToCamelCaseString (StringValues) 
    {
        let WordsArray = StringValues.split(" ");
        let CamelCaseValue = '';
        for (let index = 0; index < WordsArray.length; index++) 
        {
            let singleWord = WordsArray[index];
                singleWord.charAt(0).toUpperCase();
                singleWord =singleWord.charAt(0).toUpperCase() + singleWord.slice(1);

            CamelCaseValue +=" "+singleWord;
            
        }
        CamelCaseValue = CamelCaseValue.trim();
        return CamelCaseValue;
    }

console.log(ConverToCamelCaseString("this is my lower case string")); 

我希望上面的例子能解决你的问题。

如果有人正在使用lodash,则有_.camelCase()函数。

_.camelCase('Foo Bar');
// → 'fooBar'

_.camelCase('--foo-bar--');
// → 'fooBar'

_.camelCase('__FOO_BAR__');
// → 'fooBar'

在斯科特的具体情况下,我会这样说:

String.prototype.toCamelCase = function() {
    return this.replace(/^([A-Z])|\s(\w)/g, function(match, p1, p2, offset) {
        if (p2) return p2.toUpperCase();
        return p1.toLowerCase();        
    });
};

'EquipmentClass name'.toCamelCase()  // -> equipmentClassName
'Equipment className'.toCamelCase()  // -> equipmentClassName
'equipment class name'.toCamelCase() // -> equipmentClassName
'Equipment Class Name'.toCamelCase() // -> equipmentClassName

正则表达式将匹配以大写字母开头的第一个字符,以及空格后面的任何字母字符,即在指定的字符串中匹配2或3次。

通过将正则表达式添加到/^([A-Z])|[\s-_](\w)/g,还可以简化连字符和下划线类型的名称。

'hyphen-name-format'.toCamelCase()     // -> hyphenNameFormat
'underscore_name_format'.toCamelCase() // -> underscoreNameFormat
const toCamelCase = str =>
  str
    .replace(/[^a-zA-Z0-9]+(.)/g, (m, chr) => chr.toUpperCase())
    .replace(/^\w/, c => c.toLowerCase());