return "hello world".toLowerCase().replace(/(?:(^.)|(\s+.))/g, function(match) {
    return match.charAt(match.length-1).toUpperCase();
}); // HelloWorld

基本的方法是用匹配大写或空格的正则表达式分割字符串。然后再把碎片粘回去。技巧将处理各种方式的正则表达式分割是破坏/奇怪的浏览器。有人编写了一个库来解决这些问题;我去找找。

这是链接:http://blog.stevenlevithan.com/archives/cross-browser-split

此函数通过通过cammelcase等这些测试

Foo酒吧 ——foo bar __FOO_BAR__ - foo123Bar foo_Bar

function toCamelCase(str) { var arr= str.match(/[a-z]+|\d+/gi); return arr.map((m,i)=>{ let low = m.toLowerCase(); if (i!=0){ low = low.split('').map((s,k)=>k==0?s.toUpperCase():s).join`` } return low; }).join``; } console.log(toCamelCase('Foo Bar')); console.log(toCamelCase('--foo-bar--')); console.log(toCamelCase('__FOO_BAR__-')); console.log(toCamelCase('foo123Bar')); console.log(toCamelCase('foo_Bar')); console.log(toCamelCase('EquipmentClass name')); console.log(toCamelCase('Equipment className')); console.log(toCamelCase('equipment class name')); console.log(toCamelCase('Equipment Class Name'));

为了有效地创建一个将字符串的大小写转换为驼峰式大小写的函数，该函数还需要首先将每个字符串转换为小写，然后再将非第一个字符串的第一个字符转换为大写字母。

我的示例字符串是:

"text That I WaNt to make cAMEL case"

对于这个问题提供的许多其他解决方案返回这个:

"textThatIWaNtToMakeCAMELCase"

我认为应该是预期的，期望的输出将是这样的，其中所有的中间字符串大写字符首先转换为小写:

"textThatIWanrtToMakeCamelCase"

这可以在不使用任何replace()方法调用的情况下完成，通过使用String.prototype.split()， Array.prototype.map()和Array.prototype.join()方法:

≤ES5版本

function makeCamelCase(str) {
  return str
    .split(' ')
    .map((e,i) => i
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      : e.toLowerCase()
    )
    .join('')
}

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

我将分解每一行的功能，然后以其他两种格式提供相同的解决方案——ES6格式和字符串格式。prototype方法，不过我建议不要像这样直接扩展内置的JavaScript原型。

讲解员

function makeCamelCase(str) {
  return str
    // split string into array of different words by splitting at spaces
    .split(' ')
    // map array of words into two different cases, one for the first word (`i == false`) and one for all other words in the array (where `i == true`). `i` is a parameter that denotes the current index of the array item being evaluated. Because indexes start at `0` and `0` is a "falsy" value, we can use the false/else case of this ternary expression to match the first string where `i === 0`.
    .map((e,i) => i
      // for all non-first words, use a capitalized form of the first character + the lowercase version of the rest of the word (excluding the first character using the slice() method)
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      // for the first word, we convert the entire word to lowercase
      : e.toLowerCase()
    )
    // finally, we join the different strings back together into a single string without spaces, our camel-cased string
    .join('')
}

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

压缩ES6+(一行程序)版本

const makeCamelCase = str => str.split(' ').map((e,i) => i ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase() : e.toLowerCase()).join('')

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

字符串。原型方法版本

String.prototype.toCamelCase = function() {
  return this
    .split(' ')
    .map((e,i) => i
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      : e.toLowerCase()
    )
    .join('')
}

"text That I WaNt to make cAMEL case".toCamelCase()
// -> "textThatIWanrtToMakeCamelCase" ✅

不要使用String.prototype. tocamelcase()，因为String。原型是只读的，大多数js编译器会给你这个警告。

像我一样，那些知道字符串总是只包含一个空格的人可以使用一种更简单的方法:

let name = 'test string';

let pieces = name.split(' ');

pieces = pieces.map((word, index) => word.charAt(0)[index===0 ? 'toLowerCase' :'toUpperCase']() + word.toLowerCase().slice(1));

return pieces.join('');

祝你有愉快的一天。：）

您可以使用以下解决方案:

function toCamelCase(str){
  return str.split(' ').map(function(word,index){
    // If it is the first word make sure to lowercase all the chars.
    if(index == 0){
      return word.toLowerCase();
    }
    // If it is not the first word only upper case the first char and lowercase the rest.
    return word.charAt(0).toUpperCase() + word.slice(1).toLowerCase();
  }).join('');
}