如果你使用UITableViewController而不是UIViewController，它会自动这样做。

如果你使用uitableview来放置你的文本字段(来自Jeff Lamarche)，你可以像这样使用委托方法滚动tableview。

(注意:我的文本字段存储在一个数组中，索引与表视图中的行相同)

- (void) textFieldDidBeginEditing:(UITextField *)textField
    {

        int index;
        for(UITextField *aField in textFields){

            if (textField == aField){
                index = [textFields indexOfObject:aField]-1;
            }
        }

         if(index >= 0) 
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:index inSection:0] atScrollPosition:UITableViewScrollPositionTop animated:YES];

        [super textFieldDidBeginEditing:textField];
    }

我正在用这些，它们就像魔法一样管用:

bskey控制板- bskey控制板github

tpkeyboardavoidance - tpkeyboardavoidance github

我尝试了几乎相同的方法，并提出了一个更简单、更小的代码。 我创建了一个IBOutlet iTextView，并与IB中的UITextView相关联。

 -(void)keyboardWillShow:(NSNotification *)notification
    {
        NSLog(@"Keyboard");
        CGRect keyFrame = [[[notification userInfo]objectForKey:UIKeyboardFrameEndUserInfoKey]CGRectValue];

        [UIView beginAnimations:@"resize view" context:nil];
        [UIView setAnimationCurve:1];
        [UIView setAnimationDuration:1.0];
        CGRect frame = iTableView.frame;
        frame.size.height = frame.size.height -  keyFrame.size.height;
        iTableView.frame = frame;
        [iTableView scrollRectToVisible:frame animated:YES];
        [UIView commitAnimations];

    }

我可能错过了这一点，因为我没有阅读整篇文章，但我想到的似乎很简单。我并没有在所有情况下进行测试，但它看起来应该工作得很好。

简单地根据键盘的高度调整tableview的contentInset，然后将单元格滚动到底部:

- (void)keyboardWasShown:(NSNotification *)aNotification
{
    NSDictionary* info = [aNotification userInfo];
    CGSize kbSize = [[info objectForKey:UIKeyboardFrameBeginUserInfoKey] CGRectValue].size;

    UIEdgeInsets contentInsets = UIEdgeInsetsMake(0.0, 0.0, kbSize.height, 0.0);
    self.myTableView.contentInset = contentInsets;
    self.myTableView.scrollIndicatorInsets = contentInsets;

    [self.myTableView scrollToRowAtIndexPath:self.currentField.indexPath atScrollPosition:UITableViewScrollPositionBottom animated:YES];
}

当然

- (void)keyboardWasHidden:(NSNotification *)aNotification
{
    [UIView animateWithDuration:.3 animations:^(void) 
    {
        self.myTableView.contentInset = UIEdgeInsetsZero;
        self.myTableView.scrollIndicatorInsets = UIEdgeInsetsZero;
    }];
}

这是不是太简单了?我遗漏了什么吗?到目前为止，它对我来说还不错，但就像我说的，我还没有把它经过折腾……

基于bartjomiej semazynk解决方案的Swift 3最简单的解决方案:

override func viewDidLoad() {
    super.viewDidLoad()

    NotificationCenter.default.addObserver(self, selector: #selector(CreateEditRitualViewController.keyboardWillShow(notification:)), name: NSNotification.Name.UIKeyboardDidShow, object: nil)
    NotificationCenter.default.addObserver(self, selector: #selector(CreateEditRitualViewController.keyboardWillHide(notification:)), name: NSNotification.Name.UIKeyboardDidHide, object: nil)
}

deinit {
    NotificationCenter.default.removeObserver(self)
}

// MARK: Keyboard Notifications

@objc func keyboardWillShow(notification: NSNotification) {
    if let keyboardHeight = (notification.userInfo?[UIKeyboardFrameEndUserInfoKey] as? NSValue)?.cgRectValue.height {
        tableView.contentInset = UIEdgeInsetsMake(0, 0, keyboardHeight, 0)
    }
}

@objc func keyboardWillHide(notification: NSNotification) {
    UIView.animate(withDuration: 0.2, animations: {
        // For some reason adding inset in keyboardWillShow is animated by itself but removing is not, that's why we have to use animateWithDuration here
        self.tableView.contentInset = UIEdgeInsetsMake(0, 0, 0, 0)
    })
}